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OpenStudy (anonymous):
Help me prove LHS is equal to RHS?
3. 1 + sec^2x sin^2x = sec^2x
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OpenStudy (anonymous):
1 can be written as (cos^2x)(sec^2x).
I hope u can see the answer now
OpenStudy (anonymous):
I don't get it... :c
OpenStudy (mertsj):
Do you know that the sec is the reciprocal of the cos?
OpenStudy (anonymous):
Hang on just a minute, let me write this all out.
OpenStudy (anonymous):
Okay. I'm good. Yes, I get the reciprocals!
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OpenStudy (mertsj):
Ok. Glad you got it.
OpenStudy (anonymous):
Oh wait. You misunderstood! I don't understand the problem and answer, I was saying I'm good because I got it all written out! D:
OpenStudy (mertsj):
Replace sec^2x with 1/cos^2x
OpenStudy (anonymous):
Okay, then do I need to multiply 1/cos^2x and sin^2x?
OpenStudy (mertsj):
yes. And you will have:
\[\frac{\sin ^2x}{\cos ^2x}\]
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OpenStudy (mertsj):
What is that equal to?
OpenStudy (anonymous):
And that makes tangent, right?
OpenStudy (anonymous):
If that makes tangent, then I can use the identity tht says 1+tan^2x=sec^2x...Right?
OpenStudy (mertsj):
Yes.
OpenStudy (anonymous):
Awesome. Thank you! God bless you!
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OpenStudy (mertsj):
yw. You too.
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