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Mathematics 9 Online
OpenStudy (anonymous):

the cube root of x cubed :x to the one–third power • :x to the one–third power • x to the one–third power 1 over x to the –1 power the eleventh root of the quantity of x to the fifth times x to the fourth times x squared

OpenStudy (anonymous):

@kawaiicat123

OpenStudy (anonymous):

@sourwing are u able to help

OpenStudy (anonymous):

@kawaiicat123

OpenStudy (anonymous):

@kawaiicat123

OpenStudy (anonymous):

@helpme1.2

OpenStudy (anonymous):

please some one help me !!!!!!!!!!!!!!!!! :(

OpenStudy (anonymous):

@BlvckNight please help

OpenStudy (radar):

Is this a problem or several problems?

OpenStudy (anonymous):

its several into one

OpenStudy (anonymous):

One of your friends sends you an email asking you to explain how all of the following expressions have the same answer. the cube root of x cubed :x to the one–third power • :x to the one–third power • x to the one–third power 1 over x to the –1 power the eleventh root of the quantity of x to the fifth times x to the fourth times x squared

OpenStudy (radar):

Well one at a time: It is hard to show this without the draw or equation feature but the first one is (x^3)^(1/3) You would multiply the exponents (3)(1/3) getting x^1 or just plain x.

OpenStudy (radar):

Sorry but I have to participate in an important event.

OpenStudy (anonymous):

ok thanks for help @radar

OpenStudy (anonymous):

@HelpBlahBlahBlah @helpme1.2

OpenStudy (anonymous):

@beccaboo333

OpenStudy (helpblahblahblah):

what?

OpenStudy (anonymous):

can you help @HelpBlahBlahBlah

OpenStudy (helpblahblahblah):

ive never learned that sorry

OpenStudy (beccaboo333):

Sorry I can't really help. @Mertsj

OpenStudy (radar):

Back from the Dominoe game: Looking at the 2nd one: x to the one–third power • :x to the one–third power • x to the one–third power Note that all are to the same base. The rule for multiplying the same base is to add their exponents: So look at this as x^(1/3 + 1/3 + 1/3) = x^1 or simply x. Did you follow that?

OpenStudy (radar):

The third one: 1 over x to the –1 power: Is (1/x)^-1 When a value has a negative exponent. Move the value from a numerator to denominator or vice-versa and change the sign of the exponent. That is 1 over x to the -1 power would now become 1 under x to the + 1 power or (x^1)/1 or just x All three convert to just x.

OpenStudy (radar):

the last one: the eleventh root of the quantity of x to the fifth times x to the fourth times x squared is (x^(5 + 4 + 2))^(1/11) or (x^11)^(1/11) x^11/11 or x^1 or just x.

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