the cube root of x cubed :x to the one–third power • :x to the one–third power • x to the one–third power 1 over x to the –1 power the eleventh root of the quantity of x to the fifth times x to the fourth times x squared
@kawaiicat123
@sourwing are u able to help
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@kawaiicat123
@helpme1.2
please some one help me !!!!!!!!!!!!!!!!! :(
@BlvckNight please help
Is this a problem or several problems?
its several into one
One of your friends sends you an email asking you to explain how all of the following expressions have the same answer. the cube root of x cubed :x to the one–third power • :x to the one–third power • x to the one–third power 1 over x to the –1 power the eleventh root of the quantity of x to the fifth times x to the fourth times x squared
Well one at a time: It is hard to show this without the draw or equation feature but the first one is (x^3)^(1/3) You would multiply the exponents (3)(1/3) getting x^1 or just plain x.
Sorry but I have to participate in an important event.
ok thanks for help @radar
@HelpBlahBlahBlah @helpme1.2
@beccaboo333
what?
can you help @HelpBlahBlahBlah
ive never learned that sorry
Sorry I can't really help. @Mertsj
Back from the Dominoe game: Looking at the 2nd one: x to the one–third power • :x to the one–third power • x to the one–third power Note that all are to the same base. The rule for multiplying the same base is to add their exponents: So look at this as x^(1/3 + 1/3 + 1/3) = x^1 or simply x. Did you follow that?
The third one: 1 over x to the –1 power: Is (1/x)^-1 When a value has a negative exponent. Move the value from a numerator to denominator or vice-versa and change the sign of the exponent. That is 1 over x to the -1 power would now become 1 under x to the + 1 power or (x^1)/1 or just x All three convert to just x.
the last one: the eleventh root of the quantity of x to the fifth times x to the fourth times x squared is (x^(5 + 4 + 2))^(1/11) or (x^11)^(1/11) x^11/11 or x^1 or just x.
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