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Mathematics 8 Online
OpenStudy (anonymous):

A golfer stands 390 ft away from the hole and 40 ft below the hole. Assuming the ball is hit with an initial speed of 150 ft/s at what angle should it be hit to land in the hole.

OpenStudy (anonymous):

he just needs the help of God

OpenStudy (anonymous):

did they provide solution?

OpenStudy (anonymous):

i'm guessing 23.34 degrees or 72.51 degrees

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

So Im assuming I should start from a(t) = <0, -32> ft/sec

OpenStudy (anonymous):

Then take Integral of that to get v(t) which would be v(t) = <0, -32t> but needs to satisy the initial speed condition

OpenStudy (anonymous):

calculus? I just used simple algebra

OpenStudy (dumbcow):

150sinA gives the vertical force upwards using the height function which factors in force of gravity let initial height be -40 h(t) = -16t^2 + (150sinA)t - 40 = 0 then use 150cosA as horizontal force x(t) = (150cosA)t = 390 --> A = arccos(390/150t)

OpenStudy (anonymous):

Yes

OpenStudy (dumbcow):

@sourwing can you show your work or explain how you obtained your answer

OpenStudy (anonymous):

So What Im curious about is I think my reasoning to get v(t) was correct.......but when I take an integral again can I treat sin and cos as if they were a constant?

OpenStudy (anonymous):

exactly the same way you did. @dumbcow , except I solved for t, and plug it in h(t)

OpenStudy (dumbcow):

oh lol yeah that would be easier anyway i assumed so but for the benefit of @jasonjohnson86 a more detailed solution should be given

OpenStudy (anonymous):

well, I wasn't sure of my answer. That's why I asked him if the solution was provided.

OpenStudy (anonymous):

Ok this all helps. But I would like help with the calculus approach. I have a(t) = to the vector <0, -32> and then taking the integral v(t) = <0, -32t> a some vector C that satisfies inital conditions...therefore v(t) = <150costheta, 150sintheta - 32t>

OpenStudy (anonymous):

So When I then take the integral of v(t) can I treat sin and ccos as if they were constats so that the integral of v(t) = r(t) = <150tcos(theta), 150sin(theta) - 16t^2>?

OpenStudy (dumbcow):

yes you are correct, they are constants because you are integrating with respect to "t" not the angle

OpenStudy (anonymous):

ahhhhhhhhhhhhh thank you lol! That makes perfect sense. And I totally feel dumb didn;t even think of the algebra approach.

OpenStudy (dumbcow):

well you still have to do the algebra...the calculus only gives you the position vectors/equations however in physics those are just standard formulas so you dont have to do the calculus to derive them every time :)

OpenStudy (anonymous):

now the question is, will the golfer make it? XD

OpenStudy (anonymous):

he probably won't. He needs the help of God XDD

OpenStudy (anonymous):

But then, again God isn't that interested in golf lol

OpenStudy (dumbcow):

agreed, even if it hit the hole it would prob bounce out or ricochet off the pin

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