A golfer stands 390 ft away from the hole and 40 ft below the hole. Assuming the ball is hit with an initial speed of 150 ft/s at what angle should it be hit to land in the hole.
he just needs the help of God
did they provide solution?
i'm guessing 23.34 degrees or 72.51 degrees
yes
So Im assuming I should start from a(t) = <0, -32> ft/sec
Then take Integral of that to get v(t) which would be v(t) = <0, -32t> but needs to satisy the initial speed condition
calculus? I just used simple algebra
150sinA gives the vertical force upwards using the height function which factors in force of gravity let initial height be -40 h(t) = -16t^2 + (150sinA)t - 40 = 0 then use 150cosA as horizontal force x(t) = (150cosA)t = 390 --> A = arccos(390/150t)
Yes
@sourwing can you show your work or explain how you obtained your answer
So What Im curious about is I think my reasoning to get v(t) was correct.......but when I take an integral again can I treat sin and cos as if they were a constant?
exactly the same way you did. @dumbcow , except I solved for t, and plug it in h(t)
oh lol yeah that would be easier anyway i assumed so but for the benefit of @jasonjohnson86 a more detailed solution should be given
well, I wasn't sure of my answer. That's why I asked him if the solution was provided.
Ok this all helps. But I would like help with the calculus approach. I have a(t) = to the vector <0, -32> and then taking the integral v(t) = <0, -32t> a some vector C that satisfies inital conditions...therefore v(t) = <150costheta, 150sintheta - 32t>
So When I then take the integral of v(t) can I treat sin and ccos as if they were constats so that the integral of v(t) = r(t) = <150tcos(theta), 150sin(theta) - 16t^2>?
yes you are correct, they are constants because you are integrating with respect to "t" not the angle
ahhhhhhhhhhhhh thank you lol! That makes perfect sense. And I totally feel dumb didn;t even think of the algebra approach.
well you still have to do the algebra...the calculus only gives you the position vectors/equations however in physics those are just standard formulas so you dont have to do the calculus to derive them every time :)
now the question is, will the golfer make it? XD
he probably won't. He needs the help of God XDD
But then, again God isn't that interested in golf lol
agreed, even if it hit the hole it would prob bounce out or ricochet off the pin
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