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Mathematics 21 Online
OpenStudy (anonymous):

Simplify Cos(arctan(x))

OpenStudy (anonymous):

Can Someone help I have no idea how to do this

OpenStudy (anonymous):

hmm. i dont see a way to simplify it but you could do arctan=1/tan making it cos/tan

OpenStudy (anonymous):

seems like a waste of time to me though

OpenStudy (anonymous):

The answer is 1/sqrt(1+x^2)

OpenStudy (anonymous):

but i have no clue how to get it

OpenStudy (anonymous):

hmmmmmmmmmmm. interesting @nincompoop

OpenStudy (anonymous):

@bibby

OpenStudy (anonymous):

Heres a guy who explains it but i dont really get it http://answers.yahoo.com/question/index?qid=20080812030813AAXEPHK

OpenStudy (anonymous):

that problem is a little different from yours. and that is weird.

OpenStudy (anonymous):

Yeah there are some other ones that also say to set y= tan or whaterver but after that they dont really explain where the rest comes from

OpenStudy (anonymous):

i dont see how theyre using a pythagorean identity or even a tangent out of a cosine

OpenStudy (anonymous):

starting with let y = arctan(x)

OpenStudy (dumbcow):

cos = 1/sec = 1/sqrt(1 + tan^2) tan(arctan x) = x --> 1/sqrt(1+x^2)

OpenStudy (anonymous):

\[y = \arctan x\]\[\tan y = x\]|dw:1391084901690:dw|\[\cos y = \frac{1}{\sqrt{1+x^2}}\]\[\cos (\arctan x)=\frac{1}{\sqrt{1+x^2}}\]

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