Mathematics
8 Online
OpenStudy (anonymous):
Checking work:
Square root subtraction
Image attached
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OpenStudy (anonymous):
OpenStudy (anonymous):
sqrt(2)[6-3]
= sqrt(2)[3]
OpenStudy (anonymous):
so I think the answer is 2
OpenStudy (anonymous):
Ohh, so u combine the sqrt (2)?
OpenStudy (anonymous):
Making it swrt (2) * 6-3?
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OpenStudy (anonymous):
yes, make sure you use paranthesis
OpenStudy (anonymous):
\[6\sqrt2-3\sqrt2 = (6-3)*\sqrt2 = 3\sqrt2\]
OpenStudy (anonymous):
(just testing math equation editor :)
OpenStudy (anonymous):
Thats cool.
OpenStudy (anonymous):
oh it's working now. good good
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OpenStudy (anonymous):
Why when I do this on a calculator, do I get a decimal?
OpenStudy (anonymous):
because sqrt(2)= 1.414...
OpenStudy (anonymous):
Is there a way to calculate subtraction and addition of sqrt. on a regular calculator? Or do I need a specific calculator?
OpenStudy (anonymous):
I'm, obviously a neophyte, to this.
OpenStudy (anonymous):
u can use ur computers cal or google cal
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OpenStudy (anonymous):
ok. cool.
OpenStudy (anonymous):
Thats what messes me up. I get a decimal, when these questions are asking for answers like \[3\sqrt{2}\]
OpenStudy (anonymous):
Is it possible to get those type answers on a calculator?
OpenStudy (anonymous):
well not in a normal cal I guess
OpenStudy (anonymous):
It is always good to do maths without a cal. makes more sense
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OpenStudy (anonymous):
Ok. I guess I'll have to get used to figuring them out without a calculator.
OpenStudy (anonymous):
thank you!
OpenStudy (anonymous):
good luck with everything
OpenStudy (anonymous):
Could you check one more?
OpenStudy (anonymous):
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OpenStudy (anonymous):
@d3v13
OpenStudy (anonymous):
\[\sqrt{3}(5+8) + \sqrt{2}(-6+4)\]
OpenStudy (anonymous):
do u get it?
OpenStudy (anonymous):
I think so
OpenStudy (anonymous):
do u add sqrts. just like regular numbers right? so \[\sqrt{3}+\sqrt{2}=\sqrt{5}\]?
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OpenStudy (anonymous):
no we are not allowed to add squareroots
OpenStudy (anonymous):
you can check that using a calculator.
see whether \[\sqrt{3}+\sqrt{2}=\sqrt{5}\]
OpenStudy (anonymous):
oh ok.
OpenStudy (anonymous):
we can multiply or divide them, but can't add or subtact
OpenStudy (anonymous):
ok. That makes sense!
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OpenStudy (anonymous):
The answer here then would be:\[13\sqrt{6}-2\sqrt{4}\]
OpenStudy (anonymous):
yep
OpenStudy (anonymous):
wait
OpenStudy (anonymous):
nope that's not the answer
OpenStudy (anonymous):
no, it's not. I think it would have to be: \[13\sqrt{3}-2\sqrt{2}\]
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OpenStudy (anonymous):
yep. that's the answer
OpenStudy (anonymous):
thanks!