Question

A pump can throw a stream of water up to 29.6 m. What is the initial speed of the stream when it leaves a hoze nozzle?

Answer 1

Loss of kinetic energy = gain in potential energy

(1/2) m v^2 = m g h

v = sqrt(2 g h) take it from there.

Answer 2

KE = PE

KE = (V^2)/2
PE = GH

(Ignoring mass)

Solve for H given V =29.6 and G = 9.8

Answer 3

Cail - the question gives H= 29.6m from which the KE can be calculated (the equations are above - you can 'ignore mass' since it occurs on both sides of the equation).
As Douglas says - you then solve for V given that initial KE = final PE