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Mathematics 8 Online
OpenStudy (anonymous):

Project help. I dont understand the questions, please help.. attachment

OpenStudy (anonymous):

OpenStudy (***[isuru]***):

what do u mean by u don't understand ? all u have to do here is substitute the given values in the question to the formula and simplify it

OpenStudy (***[isuru]***):

but to do that u need the initial amount of rabbits .... the part of the question u post does not contain that ..lol

OpenStudy (anonymous):

N = N(knot)(1+1)^3 N = N(knot)(8) N(knot) / or initial population is unknow

OpenStudy (anonymous):

ah, sorry its 8192

OpenStudy (anonymous):

N=65536

OpenStudy (anonymous):

but that's not an option xD

OpenStudy (anonymous):

yeah its not :)

OpenStudy (anonymous):

lemme see might be some error grr lol

OpenStudy (anonymous):

Okay thanks :)

OpenStudy (anonymous):

Hey are you sure about value of N(knot) cause its giving me the same answer

OpenStudy (anonymous):

I might be wrong on the first part then: Daisy purchased a rabbit couple to keep as pets. Perhaps Daisy got more than she bargained for! If the population of rabbits doubles every 3 months, how many rabbits will Daisy have at the end of 3 years? ^that was the 1st part..

OpenStudy (anonymous):

ok just a moment :)

OpenStudy (anonymous):

thanks! you've been a great help :)

OpenStudy (anonymous):

haha that's what I do ^_^ welcome

OpenStudy (anonymous):

3years*(12 months/1 year) = 36 months 36 months / 3 months = 12 No. of rabbits after 36 months = 2*2^12 = 8192

OpenStudy (anonymous):

first part is true

OpenStudy (anonymous):

Hmm, then i wonder why its not working for the second part of the problem

OpenStudy (anonymous):

hmm

OpenStudy (***[isuru]***):

guys... srry for disturbing .. but did u notice the last part of the question ..."usining this formula how many rabbits daisy would have after 3 years? " If this one is related to the first question then this should ask " how many rabbits after ANOTHER 3 years" Also in the beginning the question states that "ANOTHER FORMULA " .. I think this question too asks u to bring out the value 8192 using the "ANOTHER METHOD " or in another words with the formula given... If u look at the question in that way u also have an answer... the only thing which does not satisfy this is the given growth rate... Since this does not seem to have any other rational explanation i think this could work hope this will help ya... :) pls ignore this if u guys don't agree with me

OpenStudy (anonymous):

oh yes you are right I think lemme check I was thinking the same but I got comfused

OpenStudy (anonymous):

but still if you put 2*(1+1)^3 = 16 xD

OpenStudy (anonymous):

you thing only satisfy if 8192 = N(knot)*(1+!)^3 N(knot) = 1024 xD

OpenStudy (anonymous):

This is one hard problem :)

OpenStudy (***[isuru]***):

nope.. it just jumbles it's own data ..

OpenStudy (***[isuru]***):

the problem here is with the value given for "r"

OpenStudy (***[isuru]***):

the first question says that the amount of rabbits will double every 3 months ... then after that how can "r" become 1 ? it's the problem ...

OpenStudy (anonymous):

OMG I just solved it :D

OpenStudy (anonymous):

here is the solution since from the first part we know that population of rabbits doubles after every 3 months so there are 4 times rabbit grown this mean 4+4+4 = 12 (since 3 years is the time span) so now put all this stuff in formula: N = 2*(1+1)^12 = 8192 so this model gives the same result ^_^

OpenStudy (anonymous):

:) ah i see now thanks that really helped!

OpenStudy (anonymous):

My pleasure ^_^

OpenStudy (anonymous):

And sorry for delay :/

OpenStudy (anonymous):

its okay. dont worry about it! :D thank you very much for your help! you are a man of your word (:

OpenStudy (anonymous):

:D d'aww silly don't mention it ^_^ and thank you for giving me an opportunity to learn something new ^_^

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