Question

Math Music problem help.. thanks! :)

Answer 1

What is the question..?

Answer 2

Sorry cite kicked me out and would not let me add attachment.

Answer 3

Try fully asking in Music.
There is a music section on here.

Answer 4

Sorry I can't really help.

Answer 5

Its okay. thanks tho for trying to help. Oh nd didnt post it on music cause its more of a math problem.

Answer 6

middle C, \(C_4\) has a frequency of \(2^8=256~Hz\)
\(C_5\) has twice that, which is a frequency of \(2\cdot256=2\cdot2^8=2^9~Hz\), on power of two higher. Use this pattern to get your answer.

Answer 7

typo - *one factor of two higher*

Answer 8

@beccaboo333 Math section is appropriate. Remember that math has applications everywhere!

Answer 9

Im still confused on how to solve them problem. but thanks for trying to help out :)

Answer 10

do you see that we are given middle C as\[C_4=256~Hz=2^8~Hz\]?

Answer 11

Yes i see that on the picture

Answer 12

and do you see that \(C_5\) is twice as many Hz ?

Answer 13

Yes

Answer 14

did so do you see that this means that \(\large C_5=2^9~Hz\) ?

Answer 15

No i do not see that. where do you get 2^9?

Answer 16

have you not seen the rule\[x^a\cdot x^b=x^{a+b}\]?

Answer 17

If i did i dont remember it. Sorry maths not my best subject as u can tell.

Answer 18

That's okay, just try to understand and use it now.
The rule is: if the bases are the same (x in my example) then if we multiply two terms we add their exponents.

Answer 19

\(C_5=2^8=256\)
because the next note is twice the frequency, we can find it by multiplying by 2. Remember that 2 can be written as \(2^1\), since raising a number to the power 1 does not change it. then we see that
\[C_6=2C_4=2\cdot2^8=2^1\cdot2^8=2^{8+1}=\large2^9 ~Hz\]

Answer 20

typo, should say\[C_5=2C_4=2\cdot2^8=2^1\cdot2^8=2^{8+1}=\large2^9 ~Hz\], not \(C_6=...\)