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Okay, so I was asked how many grams of O2 are required to react with 0.125g of lead (ii) sulfide. The equation is: 2PbS + 3O2 --> 2PbO + 2SO2 My answer was 0.095 g. O2, but it said I was incorrect... Did I just round the improper amount of significant figures? Should it be 0.0951 g. instead?
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I got something totally different. Can you show me what you did?
It turns out I accidentally looked at a different element when I was calculating the molar mass of Pb. Silly mistake ^ ^; Thanks for going through the trouble of figuring out the problem to help, though! I appreciate it!
No problem. Good luck.
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