Find the volume of a pyramid with triangular base bounded by vectors (1,-1,2) and (1,1,1) and a vertex located at (3,2,5)? Where shall I begin? I know the volume of the pyramid is 1/3 Base*height.
this is a linear algebra class, right?
yes
the magnitude of the cross product of two vectors can be interpreted as the area of a trapezoid|dw:1391127355743:dw|
|dw:1391127389581:dw|the base is triangular, so you want half of that still thinking on how to get the height....
oh ok. right that makes sense. for the height would you just use a projection part? P = vertex. |P*(aXb)|/||aXb|| ?
that's what I was thinking :) I just couldn't remember the projection formula. Two heads are better than one!
yea haha ok. but the formula calls for the a 3rd vector from the origin to the vertex. P is just a point not a vector correct?
it can be interpreted as a the point at the tip of the vector... so it's kinda the same thing in this case, as you will see frequently in linear algebra and multi variable calc
it's the endpoint of the vector if the vector starts at the origin, to be precise
ok that makes sense. thank you very much.
very welcome!
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