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Mathematics
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OpenStudy (kaylala):
proving identities:
(tan^2+1)/(tan+cot) = tan
12 years ago
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OpenStudy (kaylala):
@superdavesuper
12 years ago
OpenStudy (superdavesuper):
use same eqn like last time sin^2 + cos^2 = 1 to simplify n solve
but in this case, replace tan=sin/cos and cot=cos/sin first then multiply top n bottom by sin*cos....
u will need to go thro a few steps...list them out here n we will see
12 years ago
OpenStudy (kaylala):
\[((\sin \div \cos ) + 1 ) \div ((\sin \div \cos ) + (\cos \div \sin ))\]
12 years ago
OpenStudy (kaylala):
?
12 years ago
OpenStudy (superdavesuper):
yup yup
12 years ago
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OpenStudy (kaylala):
what's next?
12 years ago
OpenStudy (superdavesuper):
\[[((\sin ^{2}x/\cos ^{2}x) + 1)*(sinxcosx)]/[(sinx/cosx + cosx/sinx)*(sinxcosx)]\]
12 years ago
OpenStudy (kaylala):
will it be :
(sin^3 + cos^2sin) / (sin^2+cos^2)
12 years ago
OpenStudy (superdavesuper):
scroll up to see the 1st eqn i wrote n the bottom can be simplified to....
12 years ago
OpenStudy (kaylala):
i don't get the "n" part
what's that supposed to mean?
12 years ago
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OpenStudy (superdavesuper):
sorry sorry....i mean to say scroll up....AND use that eqn to simplify the bottom
12 years ago
OpenStudy (kaylala):
only sin gets left
12 years ago
OpenStudy (kaylala):
i cancelled out the rest
only sin gets left
@superdavesuper
12 years ago
OpenStudy (superdavesuper):
well that is because ur top part was not right....please try to expand that again :)
12 years ago
OpenStudy (kaylala):
i see now.
thanks!
12 years ago
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OpenStudy (superdavesuper):
welcome :)
12 years ago
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