OpenStudy (anonymous):

f(x)=x+1x2−1 and i got va… x=1 and ha…. y=0….. is this correct?

3 years ago
OpenStudy (anonymous):

if it is $f(x)=\frac{x+1}{x^2-1}$ then no your answers are correct, but not complete

3 years ago
OpenStudy (anonymous):

a common mistake is to set $$x^2-1=0$$ then say $$x^2=1$$ and so $$x=1$$ but the solution to $$x^2-1=0$$ is $$x=1$$ OR $$x=-1$$ so there are two vertical asympotes

3 years ago
OpenStudy (anonymous):

ok thanks

3 years ago