Question

please help with limit!! infinity/infinity form!!!

Answer 1

\[\lim_{x \rightarrow 0^+} \frac{ e^x }{ x^2-x }\]

Answer 2

i am as far as \[\lim_{x \rightarrow 0^+} \frac{ \frac{ e^x }{ x^2 } }{ 1-\frac{ 1 }{ x } }\] and im stuck

Answer 3

do i have to even do anything or do i just have to fill in 0^+?

Answer 4

As x->0+, e^x -> 1 and the denominator tends to 0-, so -infinity is the limit.

Answer 5

so where its just approaching from right i don't have to do anything else…?

If this were just x->0, i would have to do it out, correct?

Answer 6

It has two different limits. Approaching from the right, the limit is -infinity. Approaching from the left, the limit is +infinity. So the limit does not exist at x = 0

Answer 7

thank you, i just have to find it approaching form the right..

Answer 8

The limit is -infinity approaching from the right.

Answer 9

thanks

Answer 10

you are welcome.