Question

In how many different ways can a panel of 12 jurors and 2 alternates be chosen from a group of 15 prospective jurors?

Answer 1

same as the number of ways you can exclude on person from a group of 15, namely 15 ways

Answer 2

*one person

Answer 3

oh maybe we are counting jurors differently from alternates?

Answer 4

not clear from the question
we can do that too if you like

Answer 5

Im pretty sure this is a combination question

Answer 6

yeah i know,the question is this
do we count jurors differently than alternates

Answer 7

if we do, then the answer is
\[\binom{12}{15}\times \binom{3}{2}\]

Answer 8

the number of ways you can choose 12 from a set of 15, times the number of ways you can choose 2 from a set of 3

Answer 9

yeah we have to count them both

Answer 10

ok do you know how to compute those numbers?

Answer 11

\(\binom{12}{15}\) is sometimes written as \(_{15}C_{12}\)

Answer 12

i have even seen \(^{15}C_{12}\)

Answer 13

no I'm trying to figure out how to on the calulator
but I havent really learned it all yet . can it be done? or is it done all by hand>

Answer 14

you can do it with a calculator, but these two are easy

Answer 15

\[\binom{3}{2}=3\] since there are 3 ways to pick 2 out of 3

Answer 16

15nCr12 * 3nCr2

Answer 17

i think its that but I dont know how to compute it

Answer 18

\[\binom{15}{12}=\binom{15}{3}=\frac{15\times 14\times 13}{3\times 2}\] cancel first multiply last

Answer 19

you can do it instantly with wolfram
http://www.wolframalpha.com/input/?i=%2815+choose+3%29*%283+choose+2%29

Answer 20

what's a juror?

Answer 21

so the one thousand is the answer?? that seems so low

Answer 22

ahhh I see!!!!!

Answer 23

ok ok I get it