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Algebra 16 Online
OpenStudy (anonymous):

Can someone please explain to me how to figure this problem out my teacher said I did not explain enough thank you the question was asking how y=x^2 and y=2(x+3)2–4 3 ways the graph changes. How does the value of a change the graph? How does the value of h change the graph? How does the value of k change the graph? I told her y=x^2 graph has axis of symmetry x = 0 whereas y=2(x+3)2–4 graph has axis of symmetry x=-3 but it wasn't a good enough answer I would love to understand this though so I would appreciate it if someone took the time to help me

OpenStudy (whpalmer4):

\[y=x^2\] \[y=2(x+3)^2-4\] let's say that \(y = f(x)\) to start the discussion. What exactly \(f(x)\) is doesn't matter too much for much of the discussion. Think of \(f(x)\) as a little machine. You put in \(x\) and out comes a number.

OpenStudy (anonymous):

She told me to recall that the format for of a quadratic function is y=a(x-h)^2+k and each of the variables a, h and k tell you something but this whole thing is confusing so i'm not sure how to start.

OpenStudy (whpalmer4):

Now, what if we add something to the output of the machine? If we graph \(y = f(x) + 1\), the graph will look just like the graph of \(f(x)\), except each point will be shifted in the direction of positive \(y\) by 1 unit, just like as if we plotted \(f(x)\) on a transparent sheet, laid it down over our graph paper, and then shifted it up 1 unit along the \(y\) axis. Make sense so far?

OpenStudy (anonymous):

Yes that makes sense it basically all depends on the numbers you're plugging in? so like if it's a negative number its going to be shifted in the direction of negative y?

OpenStudy (whpalmer4):

that's right, adding a negative number to \(f(x)\) (or subtracting a positive number) would shift the graph downward.

OpenStudy (whpalmer4):

translation is the fancy term for shifting it without changing its shape.

OpenStudy (whpalmer4):

so, here's our first trick in our bag of tricks: if we have a function \(f(x)\), we can translate it up or down by adding or subtracting from the result of \(f(x)\). For example, \(y = f(x) + a\) produces a copy of \(y = f(x)\) shifted along the \(y\) axis by \(a\) units.

OpenStudy (whpalmer4):

Now let's consider a different trick. What if instead of adding or subtracting, we multiplied? \[y = f(x)\]\[y = a*f(x)\] What happens to the graph if \(a = 1\)?

OpenStudy (anonymous):

it would be positive one unit

OpenStudy (anonymous):

on the y axis?

OpenStudy (whpalmer4):

Suppose \(y = f(x) = x^2\). Does the graph of that look any different than that of \(y = 1*f(x) = 1*x^2\)?

OpenStudy (whpalmer4):

It's identical, I hope you'll agree :-)

OpenStudy (anonymous):

yes(: because isn't it just like multiplying it by itself so it's the same equation pretty much

OpenStudy (whpalmer4):

What about if we used \(-1\) instead of \(1\)? What is the relationship of \(y = -1*f(x)\) to \(y = f(x)\)?

OpenStudy (anonymous):

it wouldn't be identical anymore.. I think because it foes to being a negative on the graph instead of positive

OpenStudy (anonymous):

goes*

OpenStudy (whpalmer4):

Isn't it just going to be the same graph, upside down?

OpenStudy (anonymous):

yes.. i'm sorry I shouldnt have said identical it's just different on the graph

OpenStudy (anonymous):

it's when you plug in more numbers when it's not identical anymore right? or am I wrong i'm sorry I truly do not understand this

OpenStudy (whpalmer4):

Let's take a simple example. Consider the line \(y=x\). Slope is \(1\), and it goes through the origin. (0,0), (1,1), (2,2), (3,3), etc. Now look at \(y = -1*x = -x\). Slope is \(-1\), still goes through the origin. (0,0), (1,-1), (2,-2), (3,-3), etc. Isn't that the same graph, just inverted?

OpenStudy (anonymous):

Yes I think so

OpenStudy (whpalmer4):

OpenStudy (whpalmer4):

Okay, so multiplying by \(-1\) inverts a graph, or reflects it across the \(y\)-axis, if you prefer.

OpenStudy (whpalmer4):

What if we multiply by say 3? That's going to give us a graph which is 3 times as tall, right?

OpenStudy (anonymous):

Yes(:

OpenStudy (whpalmer4):

And what about if we multiply by \(-3\)?

OpenStudy (anonymous):

it would be inverted so on the graph it would reflect across the y axis as -3?

OpenStudy (anonymous):

same graph just upside down

OpenStudy (whpalmer4):

it's going to be 3 times as tall as \(f(x)\), and inverted.

OpenStudy (anonymous):

Okay I understand that(:

OpenStudy (whpalmer4):

Okay, so multiplying by a positive number scales the graph. I didn't cover the case of a positive number less than 1, but hopefully you can see that if we used say \(\frac{1}{2}\) as our multiplier, we'd get a graph that was half as tall. Multiplying by a negative number scales the graph and inverts it.

OpenStudy (whpalmer4):

Now, here's the slightly tricky one. How do we shift the graph right or left along the \(x\) axis? Any ideas?

OpenStudy (anonymous):

If we changed the "H" variable it would affect the horizontal position of the graph which is the x axis right? so we would plug that in i'm guessing

OpenStudy (whpalmer4):

if we add or subtract to/from the argument of \(f(x)\), we translate the graph to the left or the right. Any feature of the graph which normally appears at \(x=0\) will instead appear at \(x = a\) if we graph \(f(x+a)\), right?

OpenStudy (whpalmer4):

sorry, at \(x = -a\)!

OpenStudy (whpalmer4):

see, I told you it was tricky :-)

OpenStudy (anonymous):

This is so confusing but yes I think I understand what you're saying

OpenStudy (whpalmer4):

Here we have 3 parabolas. in blue, we have \(y = x^2\). in purple, \(y = (x+2)^2\). in olive, we have \(y = (x-3)^2\)

OpenStudy (whpalmer4):

I almost always have to work it out again for myself each time I explain it :-)

OpenStudy (whpalmer4):

now, do you know about vertex form for a parabola? \[y=a(x-h)^2 + k\]gives you a parabola with vertex at \((h,k)\), opening upward (like a bowl on a table) if \(a>0\) and downward if \(a < 0\)

OpenStudy (whpalmer4):

the simplest case has \(h = k = 0\), putting the vertex at the origin. Like our blue parabola in the graph.

OpenStudy (whpalmer4):

\(a\) scales and inverts the parabola, as we determined earlier. \(k\) shifts the parabola up and down. \(h\) shifts it left and right.

OpenStudy (anonymous):

Okay that makes sense but don't we make A,K, and H a actual number like they represent something and isn't that what I have to figure out for y=x2 y=2(x+3)2−4

OpenStudy (anonymous):

cause you just graphed it correct? so basically if we changed any of the numbers that represent A,K AND H it would totally change the parabola

OpenStudy (anonymous):

Basically what I should say to my teacher is y=x^2 graph has axis of symmetry x = 0 whereas y=2(x+3)2–4 graph has axis of symmetry x=-3 the 3 ways the graph can change is because of a scales and inverts the parabola, k shifts the parabola up and down. and h shifts it left and right. is that what she's asking for or is there way more to this problem that I am not understanding

OpenStudy (anonymous):

are you still there? @whpalmer4

OpenStudy (anonymous):

I have to log off because my parents need to use my laptop but I really thank you for helping me if possible do you think you could message me if I did not understand this correctly I need to give my teacher a explanation and i'm scared to give her the wrong answer so if I just gave you the wrong answer could you message me please how to do this again thank you and ttyl @whpalmer4

OpenStudy (whpalmer4):

sorry, got tied up in another problem! yes. your equation is \[y = 2(x+3)^2 -4\]compare with vertex form: \[y=a(x-h)^2+k\] to make everything match, we have \[a=2, h = -3, k=-4\] so our vertex is at \((-3,-4)\) which implies that \(x = -3\) is a line of symmetry. And because the y-coordinate of the vertex is \(-4\), we've shifted the graph down by 4 units. And finally, the \(a = 2\) means we've scaled the graph to be 2 times as tall.

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