Question

I need someone very descriptive to tell me how to work through this problem because I just can't seem to get it. Thanks! https://media.glynlyon.com/g_alg01_2013/8/2a132.gif

Answer 1

I have gained from past questions, that I am supposed to distribute.

Answer 2

\[(x \sqrt{y} \times x \sqrt{y}) + (x \sqrt{y} \times -z) + (z \times x \sqrt{y}) + (z \times -z)\]

Answer 3

leaving me with that ^

Answer 4

but don't the two middle ones cancel out?

Answer 5

so it'd be \[(x^2 \sqrt{y}) - z^2\]

Answer 6

or \[x^2 y^2 - z^2\]

Answer 7

And you are not supposed to distribute.

Answer 8

Well partly

Answer 9

haha I'm talking to myself... even online I'm forever alone

Answer 10

But you should use the formula \(a^2-b^2=(a+b)(a-b)\)

Answer 11

oh, I'm not?

Answer 12

Or the converse

Answer 13

Well you can.

Answer 14

It'd just be one step slower.

Answer 15

So never mind.

Answer 16

oh ok

Answer 17

did I get the right answer?

Answer 18

neither

Answer 19

oh dang it! hmmmm :\

Answer 20

Let's continue at \((x\sqrt y+z)(x\sqrt y-z)=(x\sqrt y)^2-z^2\).

Answer 21

It's multiple choice but that isn't one of them... :\

Answer 22

Obviously you did not see the word "continue"

Answer 23

FOIL method?

Answer 24

ohhh sorry haha ummm so... \[x^2z^2 \sqrt{y}\]

Answer 25

well FOIL method is the same as distribute

Answer 26

Which she has already done

Answer 27

and no

Answer 28

What is \((x\sqrt y)^2\)?

Answer 29

is the answer x^2y-z^2??? I'm also wondering ahahahxD

Answer 30

yes :)

Answer 31

I honestly don't know how to apply exponents to square roots so how did you do that?

Answer 32

OK, full solution first, tell me which step you understand not:
\[\Large\begin{array}{clr}
&(x\sqrt y+z)(x\sqrt y-z)\\
=&(x\sqrt y)^2-z^2&\mbox{STEP 1}\\
=&x^2(\sqrt y)^2-z^2&\mbox{STEP 2}\\
=&x^2y-z^2&\mbox{STEP 3}
\end{array}\]

Answer 33

[x sqt(y) ]^2 = x^2y.... the sqrt will be cancelled

Answer 34

btw I'm really sorry for making you answer all these questions...I feel really stupid.

Answer 35

no this site is made for this purpose X)

Answer 36

well, you need to understand the concept of square root first.

Answer 37

The square root of a number A, is a number B, which B*B=A.

Answer 38

ohhhhhhh!!! the 2nd power kinda "disappears" when you add the square root symbol!

Answer 39

because square root and square cancel out each other :D

Answer 40

yess!!!! sorry I got confused... I understand better when I can see the steps out one by one and recognize what is happening between them :)

Answer 41

Thank you so much!

Answer 42

No problem at all :)

Answer 43

haha I can get frustrating at times :]

Answer 44

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