General Identities (in Trigonometry) ADDITION AND SUBTRACTION IDENTITIES FIND THE VALUE OF: sin 15 degrees
@chmvijay
\[\sin 15=\sin \left( 45-30 \right)=\sin 45\cos 30-\cos 45\sin 30\] \[\sin 45=\frac{ 1 }{ \sqrt{2} },\cos 45=\frac{ 1 }{ \sqrt{2}},\sin 30=\frac{ 1 }{ 2 },\cos 30=\frac{ \sqrt{3} }{ 2 }\] solve.
where and how did you get sin (45-30) ???? @surjithayer
simple math 45-30=15 you can also take 60-45=15
oh does it give the same answer?
if i use either? @surjithayer
yes remember \[\sin 60=\frac{ \sqrt{3} }{ 2 },\cos 60=\frac{ 1 }{ 2 },\]
how do you know if the ooperation is + or - @surjithayer
how do you know if the ooperation is + or - at sin (45-30) ??? @surjithayer
@Preetha @thomaster @ParthKohli
Hmm! Are you aware that 15 = 45 - 30?
we know t-ratios of 0,30,45,60,90
|dw:1391182842636:dw| divide each by 4 and take the square root.
@ParthKohli yes i am
so sin30 becomes\[\frac{ \sqrt{4} }{ 4 }\] ? is it like that? then wht's the point? please help me. i really bad at this and anything related to numbers @surjithayer
\[\sqrt{\frac{ 4 }{4 }}=\sqrt{1}=1\]
\[\sqrt{\frac{ 3 }{ 4 }}=\frac{ \sqrt{3} }{ 2 }\]
\[\sin 30=\sqrt{\frac{ 1 }{4 }}=\frac{ 1 }{2 }\]
i see what about tan?
\[\sin 90=\sqrt{\frac{ 4 }{4 }}=\sqrt{1}=1\]
\[\tan 0=\frac{ \sin 0 }{ \cos 0 }=\frac{ 0 }{ 1 }=0\]
\[\tan \theta =\frac{ \sin \theta }{ \cos \theta } \]
okay thanks i'll try and figure this out..
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