Question

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the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption, what is the volume of the flask? Round the answer to two decimal places.

Answer 1

first I have to find the radis yes? 2.125

Answer 2

Let start by the cylinder. What is the area of the base?

Answer 3

\[
A=\pi r^2
\]

Answer 4

the base is 1 in

Answer 5

\[
A= \pi (1/2)^2 =\frac \pi 4
\]

Answer 6

1/2 would be the r

Answer 7

The volume of the cylinder is
\[
V_1= A h= \frac \pi 4 3 =\frac {3\pi}4
\]
Are you with me?

Answer 8

yes

Answer 9

pi*1/4

Answer 10

The Volume of a sphere is
\[
V_2 = \frac 4 3 \pi R^3
\]

Answer 11

4r^3/3+3/4

Answer 12

i need to find in cubic inches

Answer 13

V_2=\frac{4}{3} \pi \left(\frac{4.5}{2}\right)^3= 47.7129
\[
V= V_1+ V_2= \frac {3\pi}4+47.7129\approx 50.07\, in^3
\]

Answer 14

Do you understand it?

Answer 15

try to work it out now sorry im slow

Answer 16

im doing something wrong 47.7129

Answer 17

oh ok Multiply 3 by 3.1416 = 9.4248
9.4248/4 + 47.7129
2.3562+47.7129
50.0691

Answer 18

50.07

Answer 19

Thanks!!!!