Ask your own question, for FREE!
Physics 7 Online
OpenStudy (anonymous):

Three equal positive charges Q are placed at the vertices of an equilateral triangle..... the force on the centroid = 0. why?

OpenStudy (anonymous):

What happens if you push with the same force in opposite directions?

OpenStudy (anonymous):

|dw:1391186601909:dw|

OpenStudy (anonymous):

Yes. What does this net out to?

OpenStudy (anonymous):

the force on the centre is to be found

OpenStudy (anonymous):

it is 0 it it as they are include at 120

OpenStudy (anonymous):

net force =0

OpenStudy (anonymous):

Correct. Well done. They could also have been directed inward with same net result.

OpenStudy (anonymous):

Must go.

OpenStudy (anonymous):

so its because they are inclined at obtuse angle

OpenStudy (anonymous):

?

OpenStudy (mrdoe):

it is because of the symmetry of the problem, the same thing would happen if you had a perfect square with a charge at each corner etc, as long as all the angles and charges are equal, the forces will cancel in the center (this is simplistic but i hope it gives you the right idea)

OpenStudy (gudden):

Please close this question...!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!