Three equal positive charges Q are placed at the vertices of an equilateral triangle..... the force on the centroid = 0. why?
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OpenStudy (anonymous):
What happens if you push with the same force in opposite directions?
OpenStudy (anonymous):
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OpenStudy (anonymous):
Yes. What does this net out to?
OpenStudy (anonymous):
the force on the centre is to be found
OpenStudy (anonymous):
it is 0
it it as they are include at 120
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OpenStudy (anonymous):
net force =0
OpenStudy (anonymous):
Correct. Well done. They could also have been directed inward with same net result.
OpenStudy (anonymous):
Must go.
OpenStudy (anonymous):
so its because they are inclined at obtuse angle
OpenStudy (anonymous):
?
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OpenStudy (mrdoe):
it is because of the symmetry of the problem, the same thing would happen if you had a perfect square with a charge at each corner etc, as long as all the angles and charges are equal, the forces will cancel in the center (this is simplistic but i hope it gives you the right idea)