Finding final velocity? A canoeist on a lake throws a 0.145 kg baseball at 20.0 m/s to a friend in a different canoe. Each canoe with its contents has a mass of 120 kg, and is at rest initially. How fast is the first canoe moving after the pitch, assuming no friction with the water? I believe the answer is 0.024 m/s, can anyone confirm this?
@Euler271 ?? I think I've seen your posts before, and you seem very helpful!
@austinL ? Sorry if I'm not using these right. I'm new to the forum!
use conservation on momentum (linear)
of*
What is the formula again?
p=mv
20 * 0.145?
that will give you the momentum of the ball, yes
And then I use a different formula, I think... M1V1 + M2V2 = Vf (m1+m2)?
or just use the now known momentum to calculate what velocity the boat will have
since the momentum from the ball will be gained by the boat when the guy catches it
Oh, so I use the formula for velocity! I think that's what you're saying.
so the ball has momentum equal to \[p=0.145kg*20m/s= 2.9 N*s\] This momentum will be transfered to the boat due to the conservation on linear momentum as so \[2.9N*s = 120kg*v\] now solve for the velocity, no need to use the kinematic eq's
41 m/s?
\[2.9N*s/120kg = 0.2416 m/s\]
OH, I see!! Thank you so much!!!
yvw
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