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Mathematics 21 Online
OpenStudy (anonymous):

Which is the equation of the function graphed? f(x) = |x − 4| f(x) = |x| + 4 f(x) = |x + 4| f(x) = |x| − 4

OpenStudy (anonymous):

OpenStudy (anonymous):

Normally we have: \[y = mx + c\] Where \(m\) = slope and \(c\) = y-intercept. When graphing absolute values, the graph will always be in a general \(V\) form. The number outside the absolute value bars is the y-intercept. Looking at the graph, our y-intercept is \(-4\). So the functions graphed is: \[f(x) = |x| − 4\]

OpenStudy (anonymous):

Can you help with this one? Which is the direct linear variation equation for the relationship? y varies directly with x and y = 12 when x = 4. y = 2x + 4 y = 3x y = x + 8 y = x – 8

OpenStudy (anonymous):

?

OpenStudy (anonymous):

Do you know the formula for direct variation?

OpenStudy (anonymous):

:( no

OpenStudy (anonymous):

Direct variation: \[y=kx\] "Which is the direct linear variation equation for the relationship? y varies directly with x and y = 12 when x = 4" \[12 = k(4)\] Solve for \(k\): \(12\div4 = 3\) \[k = 3\] B. y = 3x

OpenStudy (anonymous):

thanks!!

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