Double check my work?
Suppose a 1,600 kg car is traveling at 20.0 m/s. What average force is needed to stop the car in 4.0 s?
20/4=5
5*1600=8000 N
My answer would be 8,000 N
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OpenStudy (anonymous):
you're wrong
OpenStudy (anonymous):
Ouch. Okay, what do you think I did wrong?
OpenStudy (anonymous):
@willagracemore
OpenStudy (anonymous):
life
OpenStudy (anonymous):
Thanks for the help. :|
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OpenStudy (anonymous):
you are welcome
OpenStudy (anonymous):
@petiteme , it looks like you are done helping Queen Bee, so could you help me now? :)
OpenStudy (petiteme):
Wow....So rude >.>
OpenStudy (anonymous):
You're telling me :/
OpenStudy (anonymous):
eyem c0nf3zd
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OpenStudy (petiteme):
You okay @FindMe678 ?
OpenStudy (anonymous):
Yes, I'm fine!
OpenStudy (anonymous):
but im not fine u r confuzzing
OpenStudy (petiteme):
Okay... Use A = V/T first
OpenStudy (anonymous):
A= 20, and T = 4?
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OpenStudy (petiteme):
Yes :)
OpenStudy (petiteme):
Divide it to get the acceleration.
OpenStudy (anonymous):
5
OpenStudy (petiteme):
Then use Force = mass x acceleration
OpenStudy (anonymous):
1600 * 5 = 8000
So I was right? Or is there more?
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OpenStudy (anonymous):
no use net force=mass x acceleration
bches u no understand newtons 2nd law