Question

You can model the population of a certain city between the years 1955 and 1955 by the radical function:

P(x)=^3√x-1940


Using this model, in what year was the population of that city 290,000?
A. 1982
B. 1986
C. 1988
D. 1992

Answer 1

Does the cube-root include 1940, or is it only over the x?

Answer 2

Its included

Answer 3

Okay, so you are given that you are looking for the population of the city equals 290,000. This means that P(x)=290,000
From here, you can solve for x.

Answer 4

can you show me but don't give me the answer I want to see how it is done

Answer 5

Sure.
\[P(x)=\sqrt[3]{x-1940}\]
\[P(x)=290,000\] Therefore, \[290,000=\sqrt[3]{x-1940}\]\[(290,000)^{3}=x-1940\]\[x=(209,000)^3+1940\]\[x=?\]

Answer 6

Ok hold on I can do dis

Answer 7

Okay :)

Answer 8

um is the 209,000 supposed to be 290,000??

Answer 9

Oh, yes, my apologies.

Answer 10

its k

Answer 11

would the answer be C??

Answer 12

Yup. :)

Answer 13

YAY I DID IT RIGHT XD

Answer 14

Well you did the work but I still learned something :3

Answer 15

I simply helped, and I am glad you learned something. :)

Answer 16

Thanks again Jack ^v^

Answer 17

No problem! :)
Good luck with the rest of your homework!