Question

anyone know finite math? sets and counting?

Answer 1

maybe

Answer 2

To help plan the number of meals to be prepared in a college cafeteria, a survey was conducted, and the following data were obtained.
127 students ate breakfast.
183 students ate lunch.
270 students ate dinner.
65 students ate breakfast and lunch.
111 students ate breakfast and dinner.
90 students ate lunch and dinner.
55 students ate all three meals.
How many students ate

Answer 3

(a) At least one meal in the cafeteria?
students

(b) Exactly one meal in the cafeteria?
students

(c) Only dinner in the cafeteria?
students

(d) Exactly two meals in the cafeteria?
students

Answer 4

that's all? i thought it would be harder :(

Answer 5

hahaha it is! I'm so confused

Answer 6

hmm it is more confusing then i tought it would be

Answer 7

haha yes

Answer 8

i have never done this type of math before, so i'm just improvising

Answer 9

let's work from the middle. 55 students ate all 3 meals. 65 students ate breakfast and lunchs, out of 55 also had dinner, so 10 students only had breakfast and lunch, correct?

Answer 10

yes

Answer 11

applying the same logic then to the other things, 35 students ate dinner and lunch (but not breakfeast) and 56 students ate breakfeast and dinner (but not lunch)

Answer 12

taking that logic one step further, we can now subtract those students from the outside circles to find the number of students that have just a single meal.

Answer 13

270 students having dinner - 56 students having dinner+breakfeast only - 55 students having all - 35 students having dinner and lunch = 124 students having only dinner

Answer 14

same logic for breakfeast makes 127 - 10-55-56 = 6 students having just lunch

Answer 15

and finaly 183 - 10-55-35 makes 83 students having just lunch (the post above this was about breakfeast)

Answer 16

now, the end result i arrived at with that logic:
6 students have breakfast only
83 have lunch only
124 have dinner only
10 have breakfast and lunch (no dinner)
35 have lunch and dinner (no breakfast)
56 have breakfast and dinner (no lunch)
55 have everything.

adding all these up gives 369 students that have at least 1 meal.

Answer 17

so if I add the three middle ones I can get the ones who had at least 2 meals?

Answer 18

the 55 students who ate 3 meals also count

Answer 19

so a is 369

Answer 20

b-213

Answer 21

c-124

Answer 22

d-156??

Answer 23

or did I do it completely wrong

Answer 24

oh d is exactly 2 meals, so d is less then that

Answer 25

a b and c seem right. Keep in mind however, i have never done this before so i am not sure if my calculations are correct

Answer 26

101??

Answer 27

alright goody!! its all right thank you so much ! you are awesome!

Answer 28

maybe check http://www.youtube.com/watch?v=LIzIhmKlYPk sometime, he can probably explain better then me

Answer 29

oh was you able to verify your answers?