11.Graph the following equations and state what the solution is?
Y = 2x + 4
y = -x – 1

Question

11.Graph the following equations and state what the solution is?
Y = 2x + 4
y = -x – 1

triciaal · Answer

EQN 1  WHEN X = 0 Y = 4  when y = 0 x = -2
eqn 2: when x = 0 y = -1 when y =0 x= -1
when they meet  2x + 4 = -x -1  solve for x
substitute in either eqn to get y

anonymous · Answer

3x = -5

triciaal · Answer

so x = -5/3 now find y

triciaal · Answer

always check your solution as the final step

anonymous · Answer

how do I find Y

triciaal · Answer

from original eqn  you have x

anonymous · Answer

so would that be 2x +4 = -5/3 -1

nikato · Answer

you could also substitute -5/3 for x in one of ur original equation

triciaal · Answer

y = 2x + 4   or y = -x -1

nikato · Answer

What u did will not help u because you have already found x

anonymous · Answer

y = -5/3x - 1

nikato · Answer

It's actually y=-(-5/3)-1
So
y=5/3 -1

triciaal · Answer

y=2(-5/3) + 4
-10/3 +4 =(-10 +12)/3 =2/3

anonymous · Answer

is the answer 2/3

jdoe0001 · Answer

$\bf {\color{red}{ Graph}}$ the following equations and state what the solution is?

anonymous · Answer

is 2/3 the slope

triciaal · Answer

you should notice it doesn't matter which one you substitute in  get the same result

jdoe0001 · Answer

pick a couple of random "x"'s for each to get a "y", draw them with the 2 points found

anonymous · Answer

what the X value and whats the Y value

triciaal · Answer

2/3 is not the slope  we were solving for y

anonymous · Answer

is y the slope

anonymous · Answer

no sorry I meant os 2/3 = y

triciaal · Answer

did you draw the graph from the points obtained when x = 0 and when y = 0?

anonymous · Answer

ok

triciaal · Answer

like jdoe0001 said above you could use random values of x find the y to get points for the graph.

anonymous · Answer

like X could be 4

whpalmer4 · Answer

Easy way to graph straight lines in a problem like this is to find the x and y intercepts by substituting 0 for one and solving for the other.  Put a ruler down on those two points and draw a straight line.  I believe that is what @triciaal was doing in her first two lines of her first post.  No need to find any other points to graph the straight lines — two points will determine the line and plugging in 0 is likely to be as easy as anything.

whpalmer4 · Answer

So for the first equation:
$$y = 2x + 4$$
Plug in $x=0$:
$$y = 2(0)+4$$$$y = 4$$First point is $(0,4)$  (that's the y-intercept, the point at which the line crosses the y-axis)
Plug in $y = 0$:
$$0 = 2x+4$$$$-2x=4$$$$x=-2$$Second point is $(-2,0)$ (the x-intercept)