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OpenStudy (faf3):

The pole vaulter runs 100m as fast as he can in 10 seconds. This gives him a velocity of 10m/s. The pole vaulter weighs 70kg. The bar is 5 m high. The pole vaulter jumps at an angle of 74 degrees How long is he in the air? How far does he travel in the air? How high did he get above the pole? Use the projectile motion formulas. Vf= Vi + gt change of y= Vit + .5gt^2 change of x= Vxt Vfy^2= Viy^2 + 2g(change of y)

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