Question

Which of the following best describes the graph of f(x) = x2 - 7x + 10?

Minimum at (1.5, -12.25) with intercepts at (5, 0) and (-2, 0)

Minimum at (-1.5, -12.25) with intercepts at (-5, 0) and (2, 0)

Minimum at (-3.5, -2.25) with intercepts at (-5, 0) and (-2, 0)

Minimum at (3.5, -2.25) with intercepts at (5, 0) and (2, 0)

Answer 1

I just answered this. Why did you close and repost?

Answer 2

http://openstudy.com/study#/updates/52ec3ff0e4b0a362a8948e13

Answer 3

find the vertex, as shown by @whpalmer4 and then find the x-intercepts by setting y = 0

Answer 4

so it would be d >?

Answer 5

@jdoe0001

Answer 6

what did you get for the vertex?

Answer 7

\(\bf \textit{vertex of a parabola}\\ \quad \\
y = {\color{red}{ a}}x^2+{\color{blue}{ b}}x+{\color{green}{ c}}\qquad



\qquad \quad
\left(-\cfrac{{\color{blue}{ b}}}{2{\color{red}{ a}}}\quad ,\quad {\color{green}{ c}}-\cfrac{{\color{blue}{ b}}^2}{4{\color{red}{ a}}}\right)\)

Answer 8

to find the x-intercepts -> \(\bf y= x^2 - 7x + 10\implies 0=x^2 - 7x + 10\) solve for "x"

Answer 9

yes, the vertex is at \[x = -\frac{-7}{2*1} = 3.5\] so D is the correct answer.

Solving for the x-intercepts,
\[x^2-7x+10 = 0\]Factor that as \[(x-5)(x-2) = 0\]\[x-5=0\]\[x=5\]\[x-2=0\]\[x=2\]Intercepts are at \((5,0),(2,0)\)