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Solve 3^x−5 = 9
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these are the answer choices A)x = −3 B)x = 2 C)x = 7 D)x = 8
\[\huge a^{-1} = \frac{ 1 }{ a^1 }\]
is this the form i need to put it in to solve?
hold on i typed the question wrong
so \[ \huge 3x^{−5} = \frac{ 3 }{ x^5 }\] moving the number of variable to the denominator turns the equation in to positive
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kk
\[3^{x-5}=9\]
sorry my bad
make the both sides to have the same constant number so \[ 3^{x-5} = 9 \]\[9 = 3^2\]so \[ 3^{x-5} = 3^2\]
so now since both sides have the same coefficient you can take just the exponent part and solve for x
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\[x-5 = 2 \] solve for x
x=7
correct
ty!
yw
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