Question

last question

Answer 1

solve \[\frac{ 2x }{ x^2+x }+\frac{ 3 }{ x-2 }-\frac{ 1 }{ x }=0\] step by step please

Answer 2

Need to get the denominator of the fractions to be the same.
Easiest is to make it (x^2+x)(x-2)(x) by multiplying the numerators by the appropriate factor. 1/a + 1/b becomes (b + a)/ab for example, by
multiplying the first term by b/b and the second by a/a, which is ok
because a/a=b/b=1

Answer 3

so what would i multiply all the denominators by?

Answer 4

That's what I am encouraging you to figure out.
Multiply the 1/x term by (x^2+x)(x-2) / (x^2+x)(x-2) , for example.