cos(x-π/6)=-.5 Find the exact solutions between 0 ≤ x ≤2π
\[ \cos( x -\frac \pi 6)= \cos(2 \frac \pi 3) \]
\[ x -\frac \pi 6= \pm \frac {2 \pi} 3 + 2 k \pi \]
\[ x = \frac \pi 6\pm \frac {2 \pi} 3 + 2 k \pi \] Choose the ones between 0 and 2 pi and you are done
i don't understand what you just did there
the last part i mean
i mean how do i pick one?
\[ \cos(u) = \cos(w) \implies x =\pm w + 2 k \pi \]
You must get two solutions
\[ x = \frac \pi 6+ \frac {2 \pi} 3 + 2 0 \pi= \frac{ 5\pi} 6 \] That is one
oh how did you know it was plus or minus 2π/3
It is not 20 pi it is 2 (0) pi=0 im the above post
\[ \cos \left(\pm\frac{2 \pi }{3}\right)=-\frac{1}{2} \]
is it easier to graph it?
\[\cos \left( x-\frac{ \pi }{6 } \right)=-\frac{ 1 }{ 2 }=-\cos \frac{ \pi }{ 3 }=\cos \left( \pi-\frac{ \pi }{ 3 } \right) ,\cos \left( \pi+\frac{ \pi }{3 } \right)\] \[\cos (x-\frac{ \pi }{6})=\cos \frac{ 2\pi }{3 },\cos \frac{ 4\pi }{3 }\] \[x-\frac{ \pi }{ 6 }=\frac{ 4\pi }{6 }+2k \pi,\frac{ 8\pi }{6 }+2k \pi ,where~ k ~is~ an ~integer.\] \[x=\frac{ 5\pi }{6 }+2k \pi,\frac{ \ 3\pi }{2 }+2k \pi ,where~ k~ is~ an~ integer\]~
could you draw out what you did there?
Here is the graph
how do i turn the decimals so it looks like pi/3 or something? i don't quite understand how to solve for x. am i suppose to add the .5 to the other side of the equation?
Please Read my older posts. I gave you some details
oh yeah i saw that, i didn't get how you got 2pi/3
I told you why \[ \cos( 2 \pi/3)=-\frac 1 2=-.5 \]
and \[ \cos( -2 \pi/3)=-\frac 1 2=-.5 \]
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