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OpenStudy (anonymous):
without this 2 more to finish ∫sin3x dx/1+cos3x let,1+cos3x=z or,d/dx(1)+d/dx(cos3x)=dz/dx or,0-sin3x.3=dz/dx or,sin3x dx=-dz/3 Now ∫sin3x dx/1+cos3x=∫-dz/3/z=-∫dz/3.1/z=-1/3∫1/z.dz=-1/3 lnz+c=-1/3 ln(1+cos3x)+c is this correct?
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hartnn (hartnn):
its correct! you're good at integrating :)
OpenStudy (anonymous):
Thank you :)
hartnn (hartnn):
you're most welcome ^_^
OpenStudy (anonymous):
^_^
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