M is the midpoint of JK. The coordinates of J are (6, 3) and the coordinates of M are (-3, 4), find the coordinates of K.
Use the midpoint formula" http://geometry.jdeer.com/Images/c1/midpoint%20formula.gif
the coordinates of the midpoint (c) can be find by this formula \[c = [ \frac{ mx_{1} + nx_{2} }{ m +n } , \frac{ my_{1} + ny_{2} }{ m + n } ]\] where where x1 , y1 will be the coordinates of the point J and x2 and y2 will be the coordinates of point K and m and n is the ratio between the distance between JM and MK got it so far ?
yea im understanding what your doing :)
since the M is the midpoint of JK , the ratio of JM to MK will be 1 ( because JM =MK) then n= 1 and m = 1 then we can simplify the equation in to \[c = [\frac{ x_{1} + x_{2} }{ 2 } , \frac{ y_{1} +y_{2} }{ 2 } ]\] ok ?
and we already know the coordinates of c ,therefor... \[( -3 , 4 ) = [ \frac{ x_{1} + x_{2} }{ 2} , \frac{ y_{1} + y_{2} }{ 2 } ]\] we also know the coordinates of J which is ( 6 , 3 ) represent by x1 and y1 , therefor \[( - 3 , 4) = [\frac{ 6 + x_{2} }{ 2 } , \frac{ 3 + y_{2} }{ 2 } ]\] now we can get 2 seperate equations from them
still following
considering the x coordinates -3 = ( 6 + x2) /2 -6 = 6 + x2 ----(1) considering the y coordinates 4 = ( 3 + y2) /2 8 = 3 + Y2 ----(2) using (1) and (2) u can find the coordinates of the point K hope this will help ya!!
did u got it or did i make it a mess ? :)
yea K =5,6 :)
is K = 5 , 6 is the given answer ?
thats what i got from it (5,6)
"thats what i got from it (5,6)" "from it" u mean wt ? the equation i wrote or something else ?
thats what i got as the answer from the equation you set up for me
mmm.... i think u need look twice... u got the x coordinate as 5 by solving -6 = 6 + x2 and y coordinate as 6 by solving 8 = 3 + Y2 try to solve them again.......
now im confised lol
ok.... lets c where did u got it wrong... can u pls tell me the steps u follow to get x coordinates as 5 ?
its ok, dont worry about it. thanks for trying, maybe its just me being tired
u r welcome !! :)
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