An observer (O) spots a plane flying at a 55° angle to his horizontal line of sight. If the plane is flying at an altitude of 21,000 ft., what is the distance (x) from the plane (P) to the observer (O)?

Question

anonymous · Answer

attachment

anonymous · Answer

Select one:
a. 20,793 feet
b. 25,636 feet
c. 28,793 feet
d. 36,585 feet

anonymous · Answer

is B the correct answer for this one @eliassaab

parthkohli · Answer

Hi!
This image suggests that sin(55) = 21000/x. Solve for x.

anonymous · Answer

would it be 12045

anonymous · Answer

@ParthKohli

parthkohli · Answer

Nope! The hypotenuse is never less than a side.

anonymous · Answer

can you help me go trough this then

parthkohli · Answer

I can!
sin(55) is approximately 0.81. 

21000/x = 0.81

anonymous · Answer

ohh... ok

anonymous · Answer

i got 20997.9

anonymous · Answer

$$\frac{ 6 }{ x }=2 $$ what is x?

anonymous · Answer

b is correct answer

anonymous · Answer

eliassaab, are you going to sit next to him while he's doing his exams, providing him with answers as well? Or do you actually want to help him understand how to work towards a solution on his own?

anonymous · Answer

$$
x \sin (55 {}^{\circ})=21000. \
x (0.819152)= 21000\
x=\frac{21000}{0.819152}=25636.3

$$

anonymous · Answer

@zimmah , I know what I am doing. My post was not the first one and after 15 posts, I decided to give him the complete proof and that is that.

anonymous · Answer

Same people just need a bit more time to understand. You don't even know what grade he's in.

anonymous · Answer

Can't believe you're a retired professor really