Question

The defining equations for the function f is f(x) = 2x^2 + 3. The defining equation for the function g is g(x) = x-5. Then the defining equation for g \circle f is:

Answer 1

18x^2 - 6x + 3
18x^2 + 6x + 3
2x^2-2
6x^3 - 10x^2 + 9x - 15

Answer 2

@hartnn

Answer 3

@surd @wolfe8 @emmigrace222 @vivalatee @niaispretty @marylou004 @LazyBoy

Answer 4

\[(gof)(x) = g[f(x)]\]

can u find g [ f(x)] ?

Answer 5

how owuld i do that?

Answer 6

ok...
let say
f(x) = 2x^2 + 5x
then do u know how to find
f(3) ?

Answer 7

nope im sorry i dont understand how to do thease

Answer 8

it's fine...
if f(x) = 2x^2 + 5x
and if they asks u to find f(3)
all u have to do is substitute 3 to the places where x is in f(x).. in this case
f(3) = 2(3)^2 + 5(3)

got it ?

Answer 9

so would i than figure out that proplem?

Answer 10

if u need to figure out the problem ... u need to understand the above thing..
basically if they give u an expression f(x) and asks u to find f(g) u have to substitute g instead of x in f(x)...

in ur case u've got
g(x) = x - 5
and u need to find
g[f(x)]
then u have to substitute f(x) instead of x in g(x)...
g(x) = x -5
= f(x) - 5
and u know that
f(x) = 2x^2 + 3
then u can write that value in place of f(x) in g[f(x)]
g[f(x)] = f(x) - 5
= 2x^2 + 3 -5
= 2x^2 - 2

that's it and hope this will help ya out!!