Question

rationalize the denominator

Answer 1

wait

Answer 2

sqrt3 - sqrt2 all over sqrt3 + sqrt 2

Answer 3

I found the conjugate denominator to be sqrt3-sqrt2

Answer 4

multiply the numerator and denominator by sqrt 3 - sqrt 2

Answer 5

yea i did that i then i got 3+2 all over 3-2. is that right?

Answer 6

denominator , 3-2 is correct :)
what about the numerator? try again....

Answer 7

\((\sqrt 3 -\sqrt 2)(\sqrt 3 -\sqrt 2) =(\sqrt 3 -\sqrt 2)^2 \\ (a-b)^2 = a^2-2ab+b^2\)

Answer 8

wait so there are to minuses and shouldnt they multiply to get a plus? 3+2? im kind of confused now

Answer 9

ooooh ok i get it
so it will 3-2

Answer 10

its like x*x = x^2
so,
\((\sqrt 3 -\sqrt 2)(\sqrt 3 -\sqrt 2) =(\sqrt 3 -\sqrt 2)^2 \)

Answer 11

and then use the formula,
\( (a-b)^2 = a^2-2ab+b^2\)

Answer 12

with a = sqrt 3
b= sqrt 2

Answer 13

ok let me try that

Answer 14

oh ok thats man got the right answer to be \[5-\sqrt{6}\]

Answer 15

thanks man*

Answer 16

yes, thats correct :)
good!