Prove that the volume of a sphere of radius R is 4/3*pi*r^3 @hartnn @ParthKohli @phi @TuringTest @ash2326 @RadEn @robtobey @jhonyy9 @Luigi0210 @Compassionate @KingGeorge @e.mccormick @shamil98 @timo86m @hba @beccaboo333 @SithsAndGiggles @Preetha @jigglypuff314 @ash2326 @ace @austinL @inkyvoyd @Jamierox4ev3r @tHe_FiZiCx99
Using what premises?
I remember I did it once for kicks in calc I by doing a volume of revolution with the equation of a circle. wio's question is the one that matters here.
I'm in calc 3 right now if that helps
then just do a triple integral in spherical coordinates; the bounds should be obvious
Do you know spherical coords?
halp
Okay you know what. You won't get any help if you act like an idiot on purpose. Do you know spherical coords or what? What can you use for the proof?
The way I would do it, a sphere is nothing but a circle rotated around the x-axis. To make this argument a bit more precise. A Sphere is the function \(f(x)=\sqrt{r^2-x^2}\) (the upper half of the circle with radius \(r\)) rotated around the \(x-\)Axis. Notice the symmetry, simplify the integral.
For spherical coordinates you were already given good answers above.
If you want to watch someone do it: http://www.youtube.com/watch?v=1Xf1U2ZRbNU
o i got it |dw:1391365823384:dw|
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