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OpenStudy (anonymous):
Help me prove LHS is equal to RHS?
(sin x/1-cos x) + (sin x/1+cos x) = 2 csc x
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OpenStudy (anonymous):
@Mertsj
OpenStudy (anonymous):
@plohrr
OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (mertsj):
Write the two fractions on the left as a single fraction using the common denominator (1-cosx)(1+cosx)
OpenStudy (anonymous):
Distribute.
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OpenStudy (anonymous):
So we get sin/1-cos^2?
OpenStudy (mertsj):
Here is what you get:
\[\frac{\sin x(1+\cos x)+\sin x(1-\cos x)}{(1-\cos ^2x)}\]
OpenStudy (anonymous):
How did you get that?
OpenStudy (anonymous):
Th original was:
\[\frac{ \sin x }{ 1-\cos x } + \frac{ \sin x }{ 1 + \cos x} = 2 \csc x\]
OpenStudy (mertsj):
Write these two fractions with a common denominator:
\[\frac{3}{7}+\frac{3}{11}=\frac{3(11)+3(7)}{7(11)}\]
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OpenStudy (mertsj):
Now apply that principal to your problem
OpenStudy (anonymous):
Oh, okay. I see now. Hang on just a minute. :P
OpenStudy (anonymous):
Does the cos x sin x and -cos x sin x cancel out?
OpenStudy (mertsj):
You now have a 2 term numerator. The two terms have sin x as a common factor. Factor it out.
OpenStudy (anonymous):
I don't get it..
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OpenStudy (mertsj):
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