Solve SA = 2ab + 2bc + 2ac for b
factor out the b from the first two terms
how?
SA = 2ab + 2bc + 2ac =b(2a+2c)+2ac
now take away that last term from both sides, and finally divide both sides of the equation by the factor that leaves only b on the RHS
-2ac=b(2ac+2c?
what does SA stand for?
It should look something like this: \[\Large SA = 2ab + 2bc + 2ac\] \[\Large SA = b(2a + 2c) + 2ac\] \[\Large SA-2ac = b(2a + 2c)\] \[\Large b(2a + 2c) = SA-2ac\] What's the last step?
it's part of the problem.
divide by -2ac?
not quite
you have to divide both sides by 2a+2c
So here are the full/complete steps to isolating b: \[\Large SA = 2ab + 2bc + 2ac\] \[\Large SA = b(2a + 2c) + 2ac\] \[\Large SA-2ac = b(2a + 2c)\] \[\Large b(2a + 2c) = SA-2ac\] \[\Large b = \frac{SA-2ac}{2a + 2c}\]
that doesnt match any of my answer choices?
What are your answer choices
a.)SA/2(a+c) b.)SA-4a/c c.)1/2 Sa-ac/a+c d.) 1/2SA/a+b+c
oh, for some reason, they're factoring out 2's (not sure why) \[\Large b = \frac{SA-2ac}{2a + 2c}\] \[\Large b = \frac{2(\frac{1}{2}SA-ac)}{2(a + c)}\] \[\Large b = \frac{\frac{1}{2}SA-ac}{a + c}\]
thank you!
@BlahblerBlah, SA stands for the surface area of the prism
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