Question

Can someone tell me if this is correct?

Answer 1

\[\int\limits \frac{ dt }{ \cos^2 t \sqrt{1+\tan t} } = \sqrt{1+\tan(t)}+C\]

Answer 2

You forgot the 2 in front of the radical

Answer 3

why is there a 2 can you please explain?

Answer 4

\[\int\limits\frac{ \sec ^{2}t }{\sqrt{1+\tan t}}dt=2\sqrt{1+\tan t}+c\]

Answer 5

\[\int\limits \left( 1+\tan t \right)^{\frac{ -1 }{ 2 }}\sec ^{2}t dt=\frac{ \left( 1+\tan t \right)^{\frac{ -1 }{ 2}+1} }{ \frac{ 1 }{2 }} +c\]

Answer 6

thanks i now understand

Answer 7

yw