Question

=√ (200)(0.23)(0.77)
how do i figure out the answer to this its part of my answer i get so far and when i hit this part i get stuck
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Answer 1

that is what it actually looks like

Answer 2

You multiply the three numbers and then take the square root.

Answer 3

200 x 0.23 x 0.77 = 35.42
sqrt(35.42) = 5.95

Answer 4

oh ok thank you i kept getting stuck on this lol

Answer 5

you are welcome.

Answer 6

notice you can write these numbers as
2*10^2 * 23*10^-2 * 7*11*10^-2
or
2*7*11*23 * 10^-2

sqr of 10^-2 is 10^-1
you get
sqr(2*7*11*23)/10

notice that there is no perfect squares (all factors are prime)

Answer 7

Do they tell you if they want the answer in decimal or scientific notation or fraction or with radical?

Answer 8

that is only part of the question but i did not figure it out right the question is a candy company claims that 13%of its plain candies are orange and a sample of 100 candies is randomly selected

Answer 9

find the mean and standard deviation for the number of orange candies in such groups of 100

Answer 10

okay i just confused you didnt i this is the same question but a different numbers i am not doing a test but a digital assignment i got a similar excersise

Answer 11

Mean = n * p
where n is the sample size and p is the probability
Here n = 100, p = 0.13
Mean = 100 * .13 = 13

Standard Deviation = sqrt(n * p * (1-p)) =
sqrt( 100 * .13 * (1 - .13)) = sqrt( 11.31) = 3.36

Answer 12

n represents 100 p represents 0.13 how do i find the value for q

Answer 13

q = 1- p

Answer 14

according to the sample its a number i will show you the example

Answer 15

r= represents the number of trials which is equal to 150
p= represents the probability of sucess in one of the trials which is equal to 0.18
q= represents the probability of a failure in one of the trials which is 0.82.

Answer 16

i cant figure out how they got the 0.82.

Answer 17

q=1-p=1-0.18 = 0.82

Answer 18

oh ok

Answer 19

i think this math is new to me i will figure it out i hope lol

Answer 20

You will figure it out. Binomial distribution quite useful when something has only two possible outcomes (true/false, present/absent, etc.).