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Mathematics 8 Online
OpenStudy (anonymous):

What is the standard deviation of the following data set rounded to the nearest tenth? 60, 40, 35, 45, 39

OpenStudy (tkhunny):

What tools have you available? What method have you at your disposal?

OpenStudy (anonymous):

first find the mean then use the formula 1/n-1((xi -u)^2 +.... +(xn - u)^2)

OpenStudy (anonymous):

u = mean, xi is u each data for x til ur last one. n= total sample

OpenStudy (anonymous):

8.7

OpenStudy (anonymous):

then u sqrt it, I forgot to mention that part

OpenStudy (anonymous):

no 8.7 isn't right

OpenStudy (anonymous):

what did u get for ur mean?

OpenStudy (anonymous):

s^2 = sum (value - mean)^2 /(n-1) where n = number of samples s = standard deviation

OpenStudy (anonymous):

then i have been lied to http://www.mathsisfun.com/data/standard-deviation-calculator.html

OpenStudy (tkhunny):

@douglaswinslowcooper How do you know it's a sample? @alexgriffin If only we could get a response from the OP.

OpenStudy (anonymous):

"data set" suggested sample to me rather than being the entire population of interest

OpenStudy (tkhunny):

Not a standard definition. No real objection, though. If that's the whole population, why in the name of reason would we care about the standard deviation?

OpenStudy (anonymous):

@tkhunny you seem to be very wise. Help me on my physics of you don't mind

OpenStudy (anonymous):

sorry for the wait I got 43.8

OpenStudy (tkhunny):

43.8 is the Mean, or Average. That is not the question.

OpenStudy (anonymous):

i was replying to @fiberdust

OpenStudy (tkhunny):

Ah. Missed that. Very good. That is the Mean. Not sure what else fiberdust is calculating. Rounding to integer, maybe?

OpenStudy (anonymous):

if u don't get these numbers right you won't get the sd right

OpenStudy (anonymous):

it's a very tedious process

OpenStudy (anonymous):

sum/n = mean

OpenStudy (anonymous):

see i used 45 twice

OpenStudy (anonymous):

219/5

OpenStudy (anonymous):

my bad

OpenStudy (anonymous):

haha its okay :)

OpenStudy (anonymous):

i had 44.8 cuz i used 45 instead of 40 mb

OpenStudy (anonymous):

so yes 43.8 is correct mean

OpenStudy (anonymous):

what i do from there

OpenStudy (anonymous):

I might be wrong how i view this but maybe others can confirm or correct me. Since you are given data sample it's going to be 1/n-1 for your formula the other part of the formula is same you will use your data sample value for example (60- mean)^2 +... continue to do each data value then add them up then use 1/n-1( ) this will be s^2 which is your variance. square root the variance to get standard deviation

OpenStudy (tkhunny):

We are ASSUMING it's a SAMPLE. State that and use n-1 in the denominator.

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