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Solve |x| + 7 < 4. a. {x | x < -11 or x > -3} b.{x | -3 < x < 3} c.Ø
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First subtract 7 from both sides |x| + 7 < 4 |x| + 7-7 < 4-7 |x| + 0 < -3 |x| < -3
Are you able to solve |x| < -3 from here?
i really dont understand this...
do you see how I subtracted 7 from both sides?
yes
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ok from here, we have to solve |x| < -3
You are basically finding the absolute values so u wanna look for what numbers can be placed as x.
however, since |x| is NEVER negative, there is no way that |x| will be less than -3 why? because being less than -3 means you have a negative number...but |x| is never negative
so |x| < -3 is impossible which means it has no solutions
so the answe is c
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that is correct, aka the empty set
ok thanks jimmy
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