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Mathematics 22 Online
OpenStudy (anonymous):

Solve |x| + 7 < 4. a. {x | x < -11 or x > -3} b.{x | -3 < x < 3} c.Ø

jimthompson5910 (jim_thompson5910):

First subtract 7 from both sides |x| + 7 < 4 |x| + 7-7 < 4-7 |x| + 0 < -3 |x| < -3

jimthompson5910 (jim_thompson5910):

Are you able to solve |x| < -3 from here?

OpenStudy (anonymous):

i really dont understand this...

jimthompson5910 (jim_thompson5910):

do you see how I subtracted 7 from both sides?

OpenStudy (anonymous):

yes

jimthompson5910 (jim_thompson5910):

ok from here, we have to solve |x| < -3

OpenStudy (calculusxy):

You are basically finding the absolute values so u wanna look for what numbers can be placed as x.

jimthompson5910 (jim_thompson5910):

however, since |x| is NEVER negative, there is no way that |x| will be less than -3 why? because being less than -3 means you have a negative number...but |x| is never negative

jimthompson5910 (jim_thompson5910):

so |x| < -3 is impossible which means it has no solutions

OpenStudy (anonymous):

so the answe is c

jimthompson5910 (jim_thompson5910):

that is correct, aka the empty set

OpenStudy (anonymous):

ok thanks jimmy

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