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Chemistry 10 Online
OpenStudy (anonymous):

Please help me...

OpenStudy (anonymous):

OpenStudy (australopithecus):

\[\Delta G = \Delta H -\Delta S(T)\] Does this help?

OpenStudy (anonymous):

am, i don't think so.. How can I use that formula?

OpenStudy (australopithecus):

Well when the change in Gibbs free energy is negative it denotes a spontaneous reaction, can you devise values for enthalpy and entropy that would allow for the reaction to be spontaneous at non-standard temperatures (273K)

OpenStudy (anonymous):

what? i don't understand...

OpenStudy (australopithecus):

https://en.wikipedia.org/wiki/Spontaneous_process

OpenStudy (australopithecus):

This might help you to understand

OpenStudy (anonymous):

okay.. i got it. :) thank you po. :)

OpenStudy (australopithecus):

po?

OpenStudy (anonymous):

"po" is a sign of our respect.. :)

OpenStudy (australopithecus):

Fair enough

OpenStudy (anonymous):

:)

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