Question

Find the average value of -3/(4x^4)+3x on the interval [1,2]

Answer 1

same thing?

Answer 2

oops that's already integrated

Answer 3

Do you know how to find average values?

Answer 4

3/x^5+3x is the orginal

Answer 5

Where are you stuck?

Answer 6

finding the area lol

Answer 7

so you take the integral of the equation between the interval [2,1], right?

Answer 8

Correct.

Answer 9

and that's the answer?

Answer 10

Basically \[
f_{avg} = \frac{F(b)-F(a)}{b-a}
\]Where \(F' = f\) and \([a,b]\) is the interval.

Answer 11

so would the answer be 621/64

Answer 12

Can I see your work?

Answer 13

What is the original function. What was your anti derivative?

Answer 14

wait one sec thats wrong

Answer 15

alright I got it 333/64

Answer 16

thanks