Surface area
Ok so I have worked out this problem several times and my answer is 2 pie. However I feel like its incorrect! Not sure what I'm doing with this one
\[2\pi \int\limits_{-5}^{5}\sqrt{100-y ^{2}}\sqrt{\frac{ y ^{2} }{ (10-y)(10+y) }}\]
This was my last step before I plugged in my numbers
is that just f'(x)^2 ? if i can recollect, isn't there 1+f'(x)^2 in the formula ?
yes thats correct. What i had written up there was the derivative squared already
oh whoops i see i did forget the 1 but i do have the one written on my paper!
ok, cool.
ok! SO.. i think i may have found my mistake here is my new answer ...
\[20\pi \sqrt{\frac{ 5 }{ 3 }}-20\pi\]
why i am i getting 200pi then
eeeek I have no idea :/
that 1+ y^2/(100-y^2) comes out to be 100/(100-y^2) and that 100 -y^2 in the denominator cancels out with sqrt(100-y^2) outside, leaving just 10......ehh, let me draw it out
|dw:1391325764071:dw| sorry for that artistic drawing :P
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