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Mathematics 20 Online
OpenStudy (anonymous):

#58 and 60 plz help

OpenStudy (anonymous):

OpenStudy (anonymous):

so ur just substituting x = a for the equation?

OpenStudy (anonymous):

for what number

OpenStudy (anonymous):

#58

OpenStudy (anonymous):

oh im sooo sorry I meant 56

OpenStudy (anonymous):

it's similar just substitute x= 4 into your equation then do same for the other number

OpenStudy (anonymous):

okso the first one is 1/2 and the second is 1/6

OpenStudy (anonymous):

isn't there more to it ?

OpenStudy (anonymous):

what does the top of page say?

OpenStudy (anonymous):

find he average rate of change btw the points

OpenStudy (anonymous):

yeah there a formula i'm sure to that so forget what i said earlier lol

OpenStudy (anonymous):

lol ok I did that first when I started working on it

OpenStudy (anonymous):

do u have the answer to problem 55

OpenStudy (anonymous):

I can chek the back of the book

OpenStudy (anonymous):

5

OpenStudy (anonymous):

what I got for 56 was.... 1/8-2 - 1/4-2 /8-4 then solved it and I got -3/4

OpenStudy (anonymous):

\[(1\div(8-2) -1/(4-2))/8-4\]

OpenStudy (anonymous):

i'm not much help sorry

OpenStudy (anonymous):

how about number 60

OpenStudy (anonymous):

well i think a part u just plug in numbers and the orginal deposit and d15 is the amount after 15 years. B part u set up the equation just plug in 17000 as the D(t) and solve for t to find the years it takes to make that amount

OpenStudy (anonymous):

I don't get that

OpenStudy (anonymous):

d(0) = 3500 + 15t^2 should get 3500 for original deposit

OpenStudy (anonymous):

17000 = 3500 +15t^2 solve for t

OpenStudy (anonymous):

d(0) = 3500 and d(15)= 3725 ?

OpenStudy (anonymous):

on 56 the way u solved it was (1/6 - 1/2) / 4 is not -3/4

OpenStudy (anonymous):

15(15)^2 +3500 does not equal 3725

OpenStudy (anonymous):

6875

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so they represent amount deposited?

OpenStudy (anonymous):

it's the total amount deposited

OpenStudy (anonymous):

ok how about b and c

OpenStudy (anonymous):

i told u on b solve for t and gave u the equation

OpenStudy (anonymous):

I got 13500+15t^2

OpenStudy (anonymous):

13500 = 15t^2

OpenStudy (anonymous):

so how do I find the year

OpenStudy (anonymous):

divide to get t^2 by itself then square root both sides

OpenStudy (anonymous):

it=30

OpenStudy (anonymous):

correct wtg

OpenStudy (anonymous):

what is (1/6 - 1/2) /4 problem 56

OpenStudy (anonymous):

-2?

OpenStudy (anonymous):

I got -3/4 I don't know

OpenStudy (anonymous):

(1/6-3/6)/(4/1)

OpenStudy (anonymous):

no it's not -3/4

OpenStudy (anonymous):

-2/6 / 4/1 ?

OpenStudy (anonymous):

so (-2/6 )/(4/1) can be rewritten as (-2/6) (1/4)

OpenStudy (anonymous):

so its -1/12

OpenStudy (anonymous):

yes correct

OpenStudy (anonymous):

ok for 60b we got 30 but hwo do we get the year

OpenStudy (anonymous):

well u get + - 30 but -30 makes no sense so it's 30 = t ...they tell us t equals years

OpenStudy (anonymous):

I don't get that

OpenStudy (anonymous):

when square root both sides u always get a positive and negative number

OpenStudy (anonymous):

ya I know how you got+30 but is 30 the final answer its not a year

OpenStudy (anonymous):

they tell us t = 0 for 1995 then t= 1 for 1996 so it's years

OpenStudy (anonymous):

well it would tak e 30 years of deposits to reach that specific amount of 17000

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

so for c is it 3500+15(15)^2 - [3500+15(0)^2]

OpenStudy (anonymous):

over 15-0

OpenStudy (anonymous):

i think so that is how u were doing problem 56 avg rate change

OpenStudy (anonymous):

does it represent the deposit?

OpenStudy (anonymous):

i think it represents the avg rate deposited per year

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