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OpenStudy (anonymous):
OpenStudy (anonymous):
so ur just substituting x = a for the equation?
OpenStudy (anonymous):
for what number
OpenStudy (anonymous):
#58
OpenStudy (anonymous):
oh im sooo sorry I meant 56
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OpenStudy (anonymous):
it's similar just substitute x= 4 into your equation then do same for the other number
OpenStudy (anonymous):
okso the first one is 1/2 and the second is 1/6
OpenStudy (anonymous):
isn't there more to it ?
OpenStudy (anonymous):
what does the top of page say?
OpenStudy (anonymous):
find he average rate of change btw the points
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OpenStudy (anonymous):
yeah there a formula i'm sure to that so forget what i said earlier lol
OpenStudy (anonymous):
lol ok I did that first when I started working on it
OpenStudy (anonymous):
do u have the answer to problem 55
OpenStudy (anonymous):
I can chek the back of the book
OpenStudy (anonymous):
5
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OpenStudy (anonymous):
what I got for 56 was.... 1/8-2 - 1/4-2 /8-4 then solved it and I got -3/4
OpenStudy (anonymous):
\[(1\div(8-2) -1/(4-2))/8-4\]
OpenStudy (anonymous):
i'm not much help sorry
OpenStudy (anonymous):
how about number 60
OpenStudy (anonymous):
well i think a part u just plug in numbers and the orginal deposit and d15 is the amount after 15 years. B part u set up the equation just plug in 17000 as the D(t) and solve for t to find the years it takes to make that amount
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OpenStudy (anonymous):
I don't get that
OpenStudy (anonymous):
d(0) = 3500 + 15t^2 should get 3500 for original deposit
OpenStudy (anonymous):
17000 = 3500 +15t^2 solve for t
OpenStudy (anonymous):
d(0) = 3500 and d(15)= 3725 ?
OpenStudy (anonymous):
on 56 the way u solved it was (1/6 - 1/2) / 4 is not -3/4
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OpenStudy (anonymous):
15(15)^2 +3500 does not equal 3725
OpenStudy (anonymous):
6875
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so they represent amount deposited?
OpenStudy (anonymous):
it's the total amount deposited
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OpenStudy (anonymous):
ok how about b and c
OpenStudy (anonymous):
i told u on b solve for t and gave u the equation
OpenStudy (anonymous):
I got 13500+15t^2
OpenStudy (anonymous):
13500 = 15t^2
OpenStudy (anonymous):
so how do I find the year
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OpenStudy (anonymous):
divide to get t^2 by itself then square root both sides
OpenStudy (anonymous):
it=30
OpenStudy (anonymous):
correct wtg
OpenStudy (anonymous):
what is (1/6 - 1/2) /4 problem 56
OpenStudy (anonymous):
-2?
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OpenStudy (anonymous):
I got -3/4 I don't know
OpenStudy (anonymous):
(1/6-3/6)/(4/1)
OpenStudy (anonymous):
no it's not -3/4
OpenStudy (anonymous):
-2/6 / 4/1 ?
OpenStudy (anonymous):
so (-2/6 )/(4/1) can be rewritten as (-2/6) (1/4)
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OpenStudy (anonymous):
so its -1/12
OpenStudy (anonymous):
yes correct
OpenStudy (anonymous):
ok for 60b we got 30 but hwo do we get the year
OpenStudy (anonymous):
well u get + - 30 but -30 makes no sense so it's 30 = t ...they tell us t equals years
OpenStudy (anonymous):
I don't get that
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OpenStudy (anonymous):
when square root both sides u always get a positive and negative number
OpenStudy (anonymous):
ya I know how you got+30 but is 30 the final answer its not a year
OpenStudy (anonymous):
they tell us t = 0 for 1995 then t= 1 for 1996 so it's years
OpenStudy (anonymous):
well it would tak e 30 years of deposits to reach that specific amount of 17000
OpenStudy (anonymous):
oh ok
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OpenStudy (anonymous):
so for c is it 3500+15(15)^2 - [3500+15(0)^2]
OpenStudy (anonymous):
over 15-0
OpenStudy (anonymous):
i think so that is how u were doing problem 56 avg rate change
OpenStudy (anonymous):
does it represent the deposit?
OpenStudy (anonymous):
i think it represents the avg rate deposited per year