Question

Find the altitude and the area of an equilateral triangle whose side is 8 cm long.

Answer 1

in equilateral traingle altitude will be perpendicular to base and bisect it

Answer 2

from pythagoras theorm
altitude=\[\sqrt{8^{2}-4^{2}}=\sqrt{64-16}=\sqrt{48}=\sqrt{16*3}=4*\sqrt{3}\]

Answer 3

area=(altitude*base)/2
\[\frac{ 4*\sqrt{3}*8 }{ 2 }=16*\sqrt{3}\]

Answer 4

@conan.195114

Answer 5

sorry, used\[h=\frac{ 2\sqrt{s(s-a)(s-b)(s-c)} }{c}\] and got \[4\sqrt{3}\]
is this correct?

Answer 6

for area i used the heron's formula and got the same answer \[16\sqrt{3}\]

thanks for helping me though
i found it too long to wait so i studied on my own.
thanks again

Answer 7

okk u can also do so ....but in heron calculation will be more