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OpenStudy (anonymous):
One diagonal of cyclic quadrilateral coincides with a diameter of whose are is 36pi cm^2. If the other diagonal which measures 8 cm meets the first diagonal at right angles , find the area of the quadrilateral and the sides.
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OpenStudy (anonymous):
|dw:1391351292798:dw|
OpenStudy (anonymous):
@jhonyy9 @TuringTest
OpenStudy (***[isuru]***):
it's easy... the most important point is One diagonal of cyclic quadrilateral coincides with a diameter |dw:1391351998901:dw|
OpenStudy (***[isuru]***):
this means that AB = diagonal of ABCD = diameter and there is this important theorem angle subtended on the circumference by a semicircle is a right angle... which means angle ACB = ADB = 90 degrees
OpenStudy (anonymous):
6 is the radius
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OpenStudy (anonymous):
thanks ..
OpenStudy (anonymous):
@***[ISURU]*** |dw:1391352436129:dw|
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