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Geometry 60 Online
OpenStudy (anonymous):

One diagonal of cyclic quadrilateral coincides with a diameter of whose are is 36pi cm^2. If the other diagonal which measures 8 cm meets the first diagonal at right angles , find the area of the quadrilateral and the sides.

OpenStudy (anonymous):

|dw:1391351292798:dw|

OpenStudy (anonymous):

@jhonyy9 @TuringTest

OpenStudy (***[isuru]***):

it's easy... the most important point is One diagonal of cyclic quadrilateral coincides with a diameter |dw:1391351998901:dw|

OpenStudy (***[isuru]***):

this means that AB = diagonal of ABCD = diameter and there is this important theorem angle subtended on the circumference by a semicircle is a right angle... which means angle ACB = ADB = 90 degrees

OpenStudy (anonymous):

6 is the radius

OpenStudy (anonymous):

thanks ..

OpenStudy (anonymous):

@***[ISURU]*** |dw:1391352436129:dw|

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