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Mathematics 23 Online
OpenStudy (anonymous):

REAL QUICK, SIMPLE ALGEBRA

OpenStudy (anonymous):

convert f(x) into general/vertex form f(x) = x^2 + 1x -6

OpenStudy (anonymous):

vertex form i know is y= a(x-h)^2 =+ k

OpenStudy (anonymous):

so u can get a general idea where the x and y cordinates cross by solving for vertical and horzontal asymptotes

OpenStudy (***[isuru]***):

f(x) = x^2 + x - 6 is already in general form

OpenStudy (anonymous):

i think complete the square gets u the vertex

OpenStudy (***[isuru]***):

to conver it tot the vertex form u must make it a perfect square

OpenStudy (anonymous):

that is completing the square

OpenStudy (anonymous):

can u show me how w the numbers its hard for me to picture this

OpenStudy (anonymous):

i see where you're getting at but dont know what to plug in and solve for

OpenStudy (***[isuru]***):

that's where completing squares comes f(x) = x^2 + x - 6 = (x + 1/2)^2 -6 - 1/4 = ( x + 1/2)^2 - 25/4

OpenStudy (anonymous):

so after completing the sq, ( x + 1/2)^2 - 25/4 is the answer???

OpenStudy (***[isuru]***):

yes

OpenStudy (***[isuru]***):

it's the vertex format .... but do u know how to do it > i mean completing squares ?

OpenStudy (anonymous):

yeah i know compl the sq but didnt kno i could do it for this example

OpenStudy (anonymous):

so by that ur vertex is (-1/2, -25/4)

OpenStudy (anonymous):

thank you sooooooooooooo much @fiberdust @***[ISURU]***

OpenStudy (anonymous):

u understand how to get the vertical and horzontal asymptotes this helps

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