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Chemistry 8 Online
OpenStudy (brinazarski):

What is the decay constant in this question?

OpenStudy (brinazarski):

OpenStudy (brinazarski):

@myininaya could you please help me?

OpenStudy (aaronq):

how many \(\beta\) emissions are there per atom of tungsten?

OpenStudy (brinazarski):

I don't know...

OpenStudy (aaronq):

hmm if you find out i can help you with the rest

OpenStudy (brinazarski):

I guess 1.07 x 10^15?

OpenStudy (brinazarski):

Or is that just in the specific amount of moles in this question?

OpenStudy (aaronq):

yeah, it's specific to the question. well essentially you need to use: \(\large [A_t]=[A_o]*e^{kt}\) to find k, the decay constant. \([A_t]\)= amount left after t time elapsed \([A_o]\)=initial amount t= time

OpenStudy (brinazarski):

So in this case would the equation just be \[1.07 = 3.76e ^{k}\] (I'm not typing out the whole numbers, but you get the idea. Is that correct?)

OpenStudy (aaronq):

close, \([A_t]\) is not 1.07, thats the number \(\beta\) emissions from W, W -> x\(\beta\) + whatever you would use it to find what the final concentration is

OpenStudy (brinazarski):

I'm not exactly sure how to use that formula...

OpenStudy (aaronq):

which one?

OpenStudy (brinazarski):

W -> xβ + whatever

OpenStudy (aaronq):

thats just showing how W decays and produced \(\beta\) particles and other stuff (not of concern). you need to find how many beta particles are produced per tungsten atom, then use that to determine how much you have left

OpenStudy (aaronq):

and by find, i don't mean calculate, i mean look around on the internet or your book

OpenStudy (brinazarski):

Funny... it says it doesn't use beta decay at 176 but electron capture... unless I'm missing something

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